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  1. Asked: May 14, 2023In: Applied Physics

    What is the formula for angular acceleration?

    Varun Kumar
    Varun Kumar
    Added an answer on May 14, 2023 at 9:55 pm

    The formula for angular acceleration is: \(\alpha = \frac{\Delta \omega}{t}\), where \(\alpha\) represents angular acceleration, \(\Delta \omega\) is the change in angular velocity, and \(t\) is the time taken.

    The formula for angular acceleration is: \(\alpha = \frac{\Delta \omega}{t}\), where \(\alpha\) represents angular acceleration, \(\Delta \omega\) is the change in angular velocity, and \(t\) is the time taken.

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  2. Asked: May 14, 2023In: Applied Physics

    How is angular velocity calculated?

    Varun Kumar
    Varun Kumar
    Added an answer on May 14, 2023 at 9:54 pm

    Angular velocity (\(\omega\)) is calculated using the formula: \(\omega = \frac{\theta}{t}\), where \(\theta\) is the angular displacement and \(t\) is the time taken.

    Angular velocity (\(\omega\)) is calculated using the formula: \(\omega = \frac{\theta}{t}\), where \(\theta\) is the angular displacement and \(t\) is the time taken.

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  3. Asked: May 14, 2023In: Applied Physics

    What is the formula for angular displacement?

    Varun Kumar
    Varun Kumar
    Added an answer on May 14, 2023 at 9:54 pm

    The formula for angular displacement is: \(\theta = \frac{s}{r}\), where \(\theta\) represents angular displacement, \(s\) is the arc length, and \(r\) is the radius.

    The formula for angular displacement is: \(\theta = \frac{s}{r}\), where \(\theta\) represents angular displacement, \(s\) is the arc length, and \(r\) is the radius.

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  4. Asked: May 14, 2023In: Applied Physics

    Explain the concept of impulse.

    Varun Kumar
    Varun Kumar
    Added an answer on May 14, 2023 at 9:52 pm

    Impulse is the product of force and the time interval over which it acts. It is equal to the change in momentum of an object. Mathematically, impulse (\(J\)) can be calculated using the equation \(J = F \cdot \Delta t\), where \(F\) is the force applied and \(\Delta t\) is the time interval over whiRead more

    Impulse is the product of force and the time interval over which it acts. It is equal to the change in momentum of an object. Mathematically, impulse (\(J\)) can be calculated using the equation \(J = F \cdot \Delta t\), where \(F\) is the force applied and \(\Delta t\) is the time interval over which the force acts. Impulse is closely related to the concept of momentum and plays a crucial role in analyzing collisions and the effects of forces on objects.

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  5. Asked: May 14, 2023In: Applied Physics

    State Newton’s second law of motion.

    Varun Kumar
    Varun Kumar
    Added an answer on May 14, 2023 at 9:50 pm

    Newton's second law of motion states that the force acting on an object is directly proportional to the rate of change of its momentum. Mathematically, it can be expressed as \(F = \frac{{\Delta p}}{{\Delta t}}\), where \(F\) is the force, \(\Delta p\) is the change in momentum, and \(\Delta t\) isRead more

    Newton’s second law of motion states that the force acting on an object is directly proportional to the rate of change of its momentum. Mathematically, it can be expressed as \(F = \frac{{\Delta p}}{{\Delta t}}\), where \(F\) is the force, \(\Delta p\) is the change in momentum, and \(\Delta t\) is the time interval over which the momentum changes.

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  6. Asked: May 14, 2023In: Applied Physics

    Explain the relationship between force and momentum.

    Vipin Chauhan
    Vipin Chauhan Professional
    Added an answer on May 14, 2023 at 9:48 pm

    Force is directly proportional to the rate of change of momentum. Mathematically, this relationship is expressed as \(F = \frac{{\Delta p}}{{\Delta t}}\), where \(F\) is the force, \(\Delta p\) is the change in momentum, and \(\Delta t\) is the time interval over which the momentum changes.

    Force is directly proportional to the rate of change of momentum. Mathematically, this relationship is expressed as \(F = \frac{{\Delta p}}{{\Delta t}}\), where \(F\) is the force, \(\Delta p\) is the change in momentum, and \(\Delta t\) is the time interval over which the momentum changes.

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  7. Asked: May 14, 2023In: Applied Physics

    Explain how the banking angle of a road is determined mathematically.

    Vipin Chauhan
    Vipin Chauhan Professional
    Added an answer on May 14, 2023 at 9:33 pm

    The banking angle (\(\theta\)) of a road can be determined mathematically using the equation \(\tan\theta = \frac{v^2}{rg}\), where \(v\) is the speed of the vehicle, \(r\) is the radius of the curve, and \(g\) is the acceleration due to gravity.

    The banking angle (\(\theta\)) of a road can be determined mathematically using the equation \(\tan\theta = \frac{v^2}{rg}\), where \(v\) is the speed of the vehicle, \(r\) is the radius of the curve, and \(g\) is the acceleration due to gravity.

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