Calculate cement, sand, aggregate value in concrete?

Solution:

Let us consider a M20 grade concrete and ratio of materials for this is (1:1.5:3)

Density Of Material

Cement=1440kg/m³

Sand= 1600kg/m³

Aggregate= 1500kg/m³

Sum of ratios = 1+1.5+3=5.5

Material required for 1m³

First of all convert wet volume to dry volume=

1×1.54 = 1.54 m³

Volume of cement =( Ratio of cement /sum of ratio)x dry volume

(  ⅕.5)x 1.54= 0.28m³

Cement volume = 0.28×1440

Therefore quantity of cement in kg =403 kg

Volume of sand = (1.5/5.5)X1.54×35.31= 14.83 cubic feet

Quantity of sand  in kg= (1.5/5.5)x1.54×1600= 672 kg

Now , Volume of aggregate = (⅗.5)x1.54=0.84m³

 Aggregate in kg =0.84×1500=1260kg