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Bar Bending Schedule for Beam:
Consider the beam has a clear span of 6m consisting of two bottom layers (2 no’s of 20 mm dia. and 2 no’s 18 mm dia.) and a top layer ( 2 no’s 16 mm dia.).
Stirrup is provided in 3 zones where 1 & 3 have 8mm dia. @140 mm c/c and 2 has 8mm dia. @190mm c/c.
Given:
Step 1: Calculation cutting length of top bar
Cutting length of top bar = clear span + development length – bend
Cutting length = L + (2 x Ld) – (2 x 2d)
= 6000 + (2 x 50 x 16) – (2 x 16)
=7568 mm
Step 2: Calculation cutting length of bottom bar
For first layer (20 dia.)
Cutting length = L + (2 x Ld) – (2 x 2d)
= 6000 + (2 x 50 x 20) – (2 x 20)
= 6920 mm
For first layer (18 dia.)
Cutting length = L + (2 x Ld) – (2 x 2d)
= 6000 + (2 x 50 x 18) – (2 x 18)
= 7764 mm
Step 3: Calculation number of stirrup
There are 3 zones first we need to calculate the length of each zone = L/3 = 6000/3 = 2000 mm
Number of stirrup for zone 1st and 3rd = (clear span / spacing ) + 1
= (2000/140) + 1 = 15.28 or 16 no’s
No. of stirrup for zone 2nd = (2000/190) – 1 = 9.52 or 10 no’s
Step 4: Cutting length of stirrup
Cross section of stirrup is 300x500mm
Effective depth (d) = 500 – (2 x 30) – (2 x 4)
= 432 mm
Cross section of stirrup is 300x500mm
Effective width (b) = 300 – (2 x 30) – (2 x 4)
= 232 mm
Cutting length = 2 (d + b) + hook – bend
= 2 x (432 + 232) + (9 x 8 x 2) – (2 x 8 x 3)
= 1424 mm = 1.42 m
Step 5: Calculate the weight of stirrup:
Total no. of stirrup = 16 + 16 + 10 = 42 no’s
Total length of stirrup = 1.42 x 42 = 59.64 m
Total weight of stirrup = 8 x 8 x 59.64/162 = 23.56 or 24 kg
Step 6: BBS of Beam:
(mm)
m
m
kg