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Home| Questions|Q 23142
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Vipin Chauhan
Vipin ChauhanProfessional
Asked: February 13, 20212021-02-13T02:16:25+05:30 2021-02-13T02:16:25+05:30In: Estimation and Costing

How to calculate bar bending schedule for beam?

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      Mohd Mujtaba
      2022-04-18T22:31:59+05:30Added an answer on April 18, 2022 at 10:31 pm

      Bar Bending Schedule for Beam:

      Consider the beam has a clear span of 6m consisting of two bottom layers (2 no’s of 20 mm dia. and 2 no’s 18 mm dia.) and a top layer ( 2 no’s 16 mm dia.).

      Stirrup is provided in 3 zones where 1 & 3 have 8mm dia. test31405652 mm c/c and 2 has 8mm dia. test15211901mm c/c.

      Given:

      • Clear span = 6000mm
      • Development Length Ld = 50d
      • Clear cover = 30mm
      • Bottom reinf. = 2 no’s 20 dia. and 2 no’s 28 dia.
      • Top reinf. = 2 no’s 16 dia.
      • Stirrup = zone 1,3 (8 dia. @ 140 mm c/c) and zone 2 (8 dia. @ 190 mm c/c)

      Step 1: Calculation cutting length of top bar

      Cutting length of top bar = clear span + development length – bend

      Cutting length = L + (2 x Ld) – (2 x 2d)

      = 6000 + (2 x 50 x 16) – (2 x 16)

      =7568 mm

      Step 2: Calculation cutting length of bottom bar

      For first layer (20 dia.)

      Cutting length = L + (2 x Ld) – (2 x 2d)

      = 6000 + (2 x 50 x 20) – (2 x 20)

      = 6920 mm

       

      For first layer (18 dia.)

      Cutting length = L + (2 x Ld) – (2 x 2d)

      = 6000 + (2 x 50 x 18) – (2 x 18)

      = 7764 mm

      Step 3: Calculation number of stirrup

      There are 3 zones first we need to calculate the length of each zone = L/3 = 6000/3 = 2000 mm

      Number of stirrup for zone 1st and 3rd = (clear span / spacing ) + 1

      = (2000/140) + 1 = 15.28 or 16 no’s

      No. of stirrup for zone 2nd = (2000/190) – 1 = 9.52 or 10 no’s

      Step 4: Cutting length of stirrup

      Cross section of stirrup is 300x500mm

      Effective depth (d) = 500 – (2 x 30) – (2 x 4)

      = 432 mm

      Cross section of stirrup is 300x500mm

      Effective width (b) = 300 – (2 x 30) – (2 x 4)

      = 232 mm

      Cutting length = 2 (d + b) + hook – bend

      = 2 x (432 + 232) + (9 x 8 x 2) – (2 x 8 x 3)

      = 1424 mm = 1.42 m

      Step 5: Calculate the weight of stirrup:

      Total no. of stirrup = 16 + 16 + 10 = 42 no’s

      Total length of stirrup = 1.42 x 42 = 59.64 m

      Total weight of stirrup = 8 x 8 x 59.64/162 = 23.56 or 24 kg

      Step 6: BBS of Beam:

        Diameter of bar

      (mm)

      Numbers Cutting length

      m

      Total length

      m

      Total weight

      kg

      Top bar 16 2 7.57 15.14 24
      Bottom bar 20 2 6.92 13.84 35
      Bottom bar 18 2 7.76 15.52 32
      Stirrup 8 42 1.42 59.64 24

       

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