Vipin ChauhanProfessional

# Find the total Energy of 5kg of water flowing with a velocity of 4m/sec under a pressure of 42 bar at a level 20metre above the datum line

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Given data : Weight of water = 5 Kg Velocity of water = 4 m/sec Pressure of water = 4.2 bar = 42828.080 Kgf/mÂ² [ w.k.t. 1bar = 10197.1621 Kgf/mÂ² ] Level of water = 20 m Total energy of water = Kinetic energy + Gravitational energy + Pressure energy Now, Kinetic energy per unit Kg of water = Â½ mVÂ² Ã—Read more

Given data :

Weight of water = 5 Kg

Velocity of water = 4 m/sec

Pressure of water = 4.2 bar = 42828.080 Kgf/mÂ² [ w.k.t. 1bar = 10197.1621 Kgf/mÂ² ]

Level of water = 20 m

Total energy of water = Kinetic energy + Gravitational energy + Pressure energy

Now, Kinetic energy per unit Kg of water = Â½ mVÂ² Ã— 1/m = Â½ VÂ² = Â½ (4)Â² = 8 J

Pressure energy per unit Kg of water = ( pressure Ã— volume ) / mass = pressure / density.

{ Density = mass / volume }

= 42828.080 / 10Â³ = 42.82 J

Gravitational energy per unit Kg of water = m Ã— g Ã— h Ã— 1/m = g Ã— h = 9.8 Ã— 20 = 196 J

Therefore, Total energy per unit Kg of water = ( 8 + 42.82 + 196 ) J = 246.82 J

Now, Total energy of 5 Kg of water = 5 Ã— 246.82 J =

1234.1J