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Home| Questions|Q 23141
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Expert Civil Latest Questions

Vipin Chauhan
Vipin ChauhanProfessional
Asked: February 13, 20212021-02-13T02:16:25+05:30 2021-02-13T02:16:25+05:30In: Estimation and Costing

How to calculate bar bending schedule for column?

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    1. Mahima Singh
      Mahima Singh
      2022-04-18T22:31:28+05:30Added an answer on April 18, 2022 at 10:31 pm

      Bar Bending Schedule of Column: – Consider the height of the column is 4.5 m and having a cross-sectional area is 300 x 300 mm and having a 40 mm of clear cover. 4 bars are going to use has a dia. of 16 mm. The 8 mm dia. of stirrups is going to use @ 160mm and @210 mm at L/3. So, calculate the cuttiRead more

      Bar Bending Schedule of Column: –

      Consider the height of the column is 4.5 m and having a cross-sectional area is 300 x 300 mm and having a 40 mm of clear cover. 4 bars are going to use has a dia. of 16 mm. The 8 mm dia. of stirrups is going to use @ 160mm and www.fbhdtj.blogspot.si - 792210 RUB TINK0FF eny mm at L/3. So, calculate the cutting length (or BBS) of bars and stirrups?

      Given Data:

      Height = 4.5 m

      Cross section = 300 x 300 mm

      Clear Cover = 40 mm

      No of vertical bar = 4 no’s

      Diameter of vertical bar = 16 mm

      Diameter of Stirrup = 8 mm

      Stirrups centre to centre spacing = @160mm or @ 210 mm

      BBS of Column =?

       

      Solution: –

      The Calculation was taken into two steps.

      1. Vertical bar calculation
      2. Cutting length of stirrups

      Vertical Bar Calculation

      Length of 1 bar = Height of column (H) + development length (Ld)

      Length of 1 bar

      = 4500 mm + 40d

      = 4500 + 40 x 16

      = 4500 + 640

      = 5140 mm or 5.140 m

      So, the length of 1 vertical bar is 5.140 m and we have a total 4 number of bars,

      Total length

      = 4 x 5.140

      = 20.56 m long vertical bar is required.

      Cutting the length of stirrups

      Cross-sectional area column is 300 mm  300mm

      Cross-section area of the stirrup

      = 300 – 2 x clear cover

      = 300 – 2 x 40

      = 300 – 80

      = 220 mm (A)

      Number of stirrups

      = 4500/3

      = 1500mm or 1.5m

      Formula = L/3 / spacing + 1

      (No of stirrups in end zone)

      = 1500 / 160

      = 9.37 no’s say 10 no’s

      There is total two zones of 160mm spacing and one zone of 210mm spacing

      = 2 x 10

      = 20 no’s (at end zones)

      At Mid Zones

      = 1500 / 210

      = 7.14 no’s say 8 no’s

      Total no of stirrups

      = 20 + 8

      = 28 no’s

      Cutting Length of one stirrup

      Formula: –

      = (4 x A) + hook – bend

      Cutting length

      = (4 x A) + 2 x 10d – 5 x 2d

      Where

      Hook = 10d

      Bend = 5  2d (5 bends in stirrup)

      d = dia. of bar

      = (4 x 220) + 2 x 10 x 8 – 2 x 5 x 8

      = 880 +160 – 80

      = 960 mm or 0.96 m

      So, we have a total 28 no’s of stirrups are going to use,

      Total length

      = 28 x 0.96

      = 27m long 8 mm bar

       

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